-1/x^2-36-13/36-x^2

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Solution for -1/x^2-36-13/36-x^2 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

-x^2-1/(x^2)-(13/36)-36 = 0

-x^2-1/(x^2)-13/36-36 = 0

-x^2-x^-2-1309/36 = 0

t_1 = x^2

-1*t_1^1-1*t_1^-1-1309/36 = 0

-1*t_1^1-1*t_1^-1-1309/36*t_1^0 = 0

(-1*t_1^2-1309/36*t_1^1-1*t_1^0)/(t_1^1) = 0 // * t_1^2

t_1^1*(-1*t_1^2-1309/36*t_1^1-1*t_1^0) = 0

t_1^1

(-1309/36)*t_1-t_1^2-1 = 0

(-1309/36)*t_1-t_1^2-1 = 0

DELTA = (-1309/36)^2-(-1*(-1)*4)

DELTA = 1708297/1296

DELTA > 0

t_1 = ((1708297/1296)^(1/2)-(-1309/36))/(-1*2) or t_1 = (-(-1309/36)-(1708297/1296)^(1/2))/(-1*2)

t_1 = ((1708297/1296)^(1/2)+1309/36)/(-2) or t_1 = (1309/36-(1708297/1296)^(1/2))/(-2)

t_1 in { ((1708297/1296)^(1/2)+1309/36)/(-2), (1309/36-(1708297/1296)^(1/2))/(-2)}

t_1 = ((1708297/1296)^(1/2)+1309/36)/(-2)

x^2-(((1708297/1296)^(1/2)+1309/36)/(-2)) = 0

1*x^2 = ((1708297/1296)^(1/2)+1309/36)/(-2) // : 1

x^2 = ((1708297/1296)^(1/2)+1309/36)/(-2)

t_1 = (1309/36-(1708297/1296)^(1/2))/(-2)

x^2-((1309/36-(1708297/1296)^(1/2))/(-2)) = 0

1*x^2 = (1309/36-(1708297/1296)^(1/2))/(-2) // : 1

x^2 = (1309/36-(1708297/1296)^(1/2))/(-2)

x belongs to the empty set

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